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Question

Question 4(iv)
Factorise
x4(xz)4

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Solution

x4(xz)4=(x2)2[((xz)2)2]=[x2(xz)2][x2+(xz)2]=[x(xz)][x+(xz)][x2+(xz)2]=z(2xz)[x2+x22xz+z2]=z(2xz)(2x22xz+z2)

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