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Question

Question 82 (iv)

Subtract

3t44t3+2t26t+6 from4t4+8t34t22t+11

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Solution

The required difference is given by
(4t4+8t34t22t+11)(3t44t3+2t26t+6)
4t4+8t34t22t+113t4+4t32t2+6t6
=(4t43t4)+(8t3+4t3)+(4t22t2)+(2t+6t)+(116)
[grouping like terms]
=7t4+12t36t2+4t+5


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