Question 58 (j)
Subtract:
11−15y2 from y3−15y2−y−11.
We have, y3−15y2−y−11−(11−15y2)= y3−15y2−y−11−11+15y2 On combining the like terms, = y3−15y2+15y2−y−11−11=y3−y−22