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Reciprocal of a Number

Question 94 j...

Question

Question 94 (j)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18}$ .

Find $x \div (y \div z)$ .

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Solution

Given, $x = \frac{- 4}{9}, y = \frac{5}{12} a n d z = \frac{7}{18}$
Here, $x \div (y \div z) = \frac{- 4}{9} \div (\frac{5}{12} \div \frac{7}{18}) = \frac{- 4}{9} \div (\frac{5}{12} \times \frac{18}{7})$ [ $∵$ reciprocal of $\frac{7}{18} = \frac{18}{7}$ ]
$= \frac{- 4}{9} \div \frac{15}{14} = \frac{- 4}{9} \times \frac{14}{15}$ [ $∵$ reciprocal of $\frac{15}{14} = \frac{14}{15}$ ]

$= \frac{- 56}{135}$

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Similar questions

Question 94 (g)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18}$

Find $(x \div y) \times z$ .

Question 94 (h)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18}$

Find $(x - y) + z$ .

Question 94 (i)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$

Find $x + (y + z)$ .

Question 94 (k)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$ find
$x - (y + z)$

Verify the property: $x \times (y \times z) = (x \times y) \times z b y t a k i n g :$

(i) $x = \frac{- 7}{3}, y = \frac{12}{5}, z = \frac{4}{9}$

(ii) $x = 0, y = \frac{- 3}{5}, z = \frac{- 9}{4}$

(iii) $x = \frac{1}{2}, y = \frac{5}{- 4}, z = \frac{- 7}{5}$

(iv) $x = \frac{5}{7}, y = \frac{- 12}{13}, z = \frac{- 7}{18}$

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Reciprocal of a Number

Standard VII Mathematics

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