Question

Question 94 (g)

Taking $x=\frac{-4}{9},y=\frac{5}{12}$ and $z=\frac{7}{18}$

Find $(x÷y)\times z$.

Answer 1

Given , $x=\frac{-4}{9},y=\frac{5}{12}andz=\frac{7}{18}$
We have,$(x÷y)\times z=(\frac{-4}{9}÷\frac{5}{12})\times \frac{7}{18}$
$=(\frac{-4}{9}\times \frac{12}{5})\times \frac{7}{18}$ [$\because Reciprocalof\frac{5}{12}=\frac{12}{5}$]
$=\left(\frac{-4\times 12\times 7}{9\times 5\times 18}\right)$ [$\because$ product of rational number = $\frac{productofnumerators}{productofdenominators}$]
$=\frac{-56}{135}$