Question

Jessy tossed a coin and rolled a dice having 6 faces. The probability of getting head on the coin and 4 on the dice is (upto two decimal places).

Answer 1

When a coin is tossed their is a possibility of getting either heads or tails.

And, our favourable outcome is head.

So, probability of getting Heads be $\text{P(H)}=\frac{\text{Favourable number of outcome}}{\text{total number of outcome}}$

$\Rightarrow \text{P(H)}=\frac{1}{2}$

Now,
Total number of outcomes of dice will be $=6$
i.e {1, 2, 3, 4, 5, 6}

Probability of getting $4$ on dice is $\text{P(4)}=\frac{\text{Favourable number of outcome}}{\text{total number of outcome}}$

$\Rightarrow \text{P(4)}=\frac{1}{6}$

Since, both the events are independent, the probability of getting head on a coin and $4$ on a dice is $\text{P(E) = P(H)}\times \text{P(4)}$

$\Rightarrow \text{P(E)}=\frac{1}{2}\times \frac{1}{6}=\frac{1}{12}=\mathrm{0.08333...}$

But we have to calculate upto two decimal places so required probability will be $\mathrm{0.08.}$