John’s age is x. His father’s age is 5 less than thrice of John's age, and his son’s age is a sixth of John’s age. Find John’s age if his father’s age is more than 17 times his son’s age.
A
x>28
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B
x>32
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C
x>34
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D
x>30
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Solution
The correct option is Dx>30 John’s age is x.
John’s father’s age = 3x - 5
John’s son’s age =x6
Since the ratio of John’s father’s age to John’s son’s age is greater than 17, we have: 3x−5x6>17 3x−5>17×x6 6×(3x−5)>17×x 18x−30>17x 18x−17x>30 x>30
John’s age will be greater than 30 years.