Julia and Cescca are invited for a party. Julia leaves home in car at 9:05 am, driving at an average speed of $10$ miles per hour. After $15$ minutes , Cessca leaves in a car at an average speed of $25$ miles per hour.At what time Cescca catch up to her?

9 : 15

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9 : 20

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9 : 26

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9 : 30

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Solution

The correct option is C $9 : 30$ AM
We know the formula Speed $=$ distance/time
Julia's distance $=$ Cesca distance
$\Rightarrow 10 t = 25 (t - 15)$
$\Rightarrow 10 t = 25 t - 375$
$\Rightarrow 15 t = 375$
$\Rightarrow t = 25$ minutes.
So, Cescca catch up Julia $= 9 : 05 + 0.25 = 9 : 30$ AM

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Julia and Cescca are invited for a party. Julia leaves home in car at 9:05 am, driving at an average speed of 10 miles per hour. After 15 minutes , Cessca leaves in a car at an average speed of 25 miles per hour.At what time Cescca catch up to her?

The correct option is C 9:30AMWe know the formula Speed = distance/timeJulia's distance = Cesca distance⇒10t=25(t−15)⇒10t=25t−375⇒15t=375⇒t=25 minutes.So, Cescca catch up Julia =9:05+0.25=9:30 AM

Julia and Cescca are invited for a party. Julia leaves home in car at 9:05 am, driving at an average speed of $10$ miles per hour. After $15$ minutes , Cessca leaves in a car at an average speed of $25$ miles per hour.At what time Cescca catch up to her?

The correct option is C $9 : 30$ AM
We know the formula Speed $=$ distance/time
Julia's distance $=$ Cesca distance
$\Rightarrow 10 t = 25 (t - 15)$
$\Rightarrow 10 t = 25 t - 375$
$\Rightarrow 15 t = 375$
$\Rightarrow t = 25$ minutes.
So, Cescca catch up Julia $= 9 : 05 + 0.25 = 9 : 30$ AM