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Question

Justify whether it is true to say that the sequence having following nth term is an A.P.
(i) an = 2n − 1 (ii) an = 3n2 + 5 (iii) an = 1 + n + n2

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Solution

(i)

Consider the expression an = 2n − 1,
For n = 1, a1 = 2(1) − 1 = 1
For n = 2, a2 = 2(2) − 1 = 3
For n = 3, a3 = 2(3) − 1 = 5
For n = 4, a4 = 2(4) − 1 = 7
The first four terms are 1, 3, 5, 7.
The difference between each consecutive term is 2.
Hence this is an A.P.

(ii)
Consider the expression an = 3n2 + 1,
For n = 1, a1 = 3(12) + 1 = 8
For n = 2, a2 = 3(22) + 1 = 17
For n = 3, a3 = 3(32) + 1 = 32
For n = 4, a4 = 3(42) + 1 = 53
The first four terms are 8, 17, 32, 53.
The difference between each consecutive is not same.
Hence this is not an A.P.

(iii)
Consider the expression an = 1 + n + n2,
For n = 1, a1 = 1 + 1 + 1 = 3
For n = 2, a2 = 1 + 2 + 4 = 7
For n = 3, a3 = 1 + 3 + 9 = 13
For n = 4, a4 = 1 + 4 + 16 = 21
The first four terms are 3, 7, 13, 21.
The difference between each consecutive term is not same.
Hence this is not an A.P.


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