K1 and K2 are the respective equilibrium constant for the reactions: (i) XeF6(g)+H2O(g)⇌XeOF4(g)+2HF(g);K1 (ii) XeO4(g)+XeF6(g)⇌XeOF4(g)+XeO1F2;K2 The equilibrium constant for the reaction XeO4(g)+2HF(g)⇌XeO3F2(g)+H2O(g) will be:
A
K1K22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
K1−K2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
K1K2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
K2K1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is DK2K1 XeF6(g)+H2O(g)⇌XeOF4(g)+2HF(g)