$K_{2} C r_{2} O_{7} + S O_{2} H^{+} - - \to$ Products.
In this reaction, the final oxidation states of sulphur and chromium are:

+3, +6

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+6, +3

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+4, +3

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+6, +6

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Solution

The correct option is B +6, +3
$K_{2} C r_{2} O_{7} + 3 S O_{2} + H_{2} S O_{4} \to K_{2} S O_{4} + C r_{2} (S O_{4})_{3} + H_{2} O$

In $C r_{2} (S O_{4})_{3}$ , the oxidation state of $C r$ is +3 and that of $K_{2} S O_{4}$ is +6.

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