Question

$K_{3}Co{F}_6$ is a high spin complex. What is the hybridisation of $Co$ atom in this complex?

• A. $s{p}^{3}d$
• B. $s{p}^3{d}^2$
• C. $d^{2}s{p}^3$
• D. $ds{p}^2$

Answer 1

The correct option is B $s{p}^3{d}^2$

High spin complexes are formed by weak field ligands involving outer orbitals. It is a complex with coordination number $=6$, hence the hybridisation will be either $d^{2}s{p}^3$ (inner orbital complex) or $s{p}^3{d}^2$ (outer orbital complex).

Since here it is high spin complex so outer orbitals are involved and hybridisation is $s{p}^3{d}^2$.