$K_{4} [F e (C N)_{6}]$ is called :

potassium hexacyanidoferrate

(I I)

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potassium ferricyanate

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potassium ferricyanide

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prussian blue

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Solution

The correct option is A potassium hexacyanidoferrate $(I I)$
$K_{4} [F e (C N)_{6}]$
+4 +2
potassium hexacyanidoferrate $(I I)$
$K_{3} [F e (C N)_{6}]$
+3
potassium ferricyanide (prussian blue)

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Similar questions

{F e}^{2 +}

K_{3} [{F e (C N)}_{6}]

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K_{4} [{F e (C N)}_{6}]

K_{3} [F e (C N)_{6}]

K_{4} [F e {(C N)}_{6}]

50

300 K

(K_{4} [F e (C N)_{6}])

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