MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Law of Mass Action

K c for 2S...

Question

$K_{c}$ for $2 S O_{2} + O_{2} ⇌ 2 S O_{3}$ in a $10 l i t$ flask at certain $T$ is $100 l i t . m o l^{- 1}$ . Now , if equilibrium pressures of $S O_{2}$ and $S O_{3}$ are equal , then mass of $O_{2}$ present at equilibrium is:

A

6.4 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

12.8 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

3.2 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

16 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $3.2 g$
It is given that the equilibrium pressures of $S O_{2}$ and $S O_{3}$ are equal. Therefore, the number of moles of $S O_{2}$ and $S O_{3}$ are also equal at equilibrium.
$a - 2 x = 2 x$
$a = 4 x$
$K_{c} = \frac{[S O_{3}]^{2}}{[S O_{2}]^{2} [O_{2}]}$
$100 = \frac{1}{[O_{2}]}$ (Since concentration of $S O_{3}$ and $S O_{2}$ are equal)

$100 = \frac{10}{a - x} = \frac{10}{3 x}$
$3 x = 0.1$
Number of moles of $O_{2}$ at equilibrium are $a - x = 3 x = 0.1$
Mass of $O_{2} = 0.1 \times 32 = 3.2 g$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The equilibrium constant

k_{p}

for the reaction

2 S O_{2} + O_{2} \Leftrightarrow 2 S O_{3}

a t m^{- 1}

. What would be the partial pressure of

O_{2}

, if the equilibrium pressures of

S O_{2}

S O_{3}

K_{c}

for the following equilibrium when the equilibrium concentration of each substance is:

[S O_{2}] = 0.60 M, [O_{2}] = 0.82 M

[S O_{3}] = 1.90 M

2 S O_{2} + O_{2} ⇌ 2 S O_{3}

Q. In the equilibrium,

2 {S O}_{2} + O_{2} ⇌ 2 S O_{3}

the partial pressure of

{S O}_{2}, O_{2}

S O_{3}

are 0.662,0.10 and 0.331 respectively.What should be the partial pressure of oxygen so that the equilibrium concentration of

{S O}_{2}

S O_{3}

Q. The equilibrium mixture for

{2 S O}_{2} + O_{2} ⇌ {2 S O}_{3}

present in I L vessel at 600C contains 0.50, 0.12, and 5.0 moles of

S O_{2}, O_{2}

S O_{3}

respectively.
A) Calculate

K_{C}

for the given change at

600^{0} C

.
B) Also calculate

K_{P}

.

Q. Homogeneous equilibrium :

K_{c}

is gaseous system
A mixture of

S O_{3}, S O_{2}

O_{2}

gases is maintained at equilibrium in

10

litre flask at a temperature at which

K_{c}

for the reaction,

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{2} (g)

100 m o l^{- 1}

litre. At equilibrium.
(a) If no. of mole of

S O_{3}

S O_{2}

in flask are same, how many mole of

O_{2}

are present?
(b) If no. of mole of

S O_{3}

in flask are twice the no. of mole of

S O_{2}

, how many mole of

O_{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Laws of Mass Action

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Law of Mass Action

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon