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Question

Kp=0.04 atm at 899 K for the equilibrium shown below. What is the equilibrium concentration of C2H6 when it is placed in a flask at 4.0 atm pressure and allowed to come to equilibrium?
C2H6(g)C2H4(g)+H2(g)


Solution

Let p be the pressure exerted by ethene and hydrogen gas (each) at equilibrium. Now, according to the reaction,
C2H6(g)C2H4(g)+H2(G)Initial cone.4.0 atm00At equilibrium4.0ppp

We can write
Pc2H4×PH2PC2H6=Kpp×p4.0p=0.04p2=0.160.04pp2+0.04p0.16=0
Now, p=0.04±(0.04)24×1×(0.16)2×1=0.04±0.802
=0.762     (Taking positive value)
=0.38
Hence, at equilibrium,
[C2H6]=4p=40.38=3.62 atm

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