Question

$K_{s}p$ of AgCl is $1\times {10}^{-10}$ . Its solubility in $0.1MKN{O}_3$ will be:

• A. ${10}^{-5}moles/litre$
• B. $>{10}^{-5}moles/litre$
• C. $<{10}^{-5}moles/litre$
• D. none of these

Answer 1

Answer: (A)

${10}^{-5}moles/litre$

$AgCl\to A{g}^{+}+C{l}^{-}$

$K_{sp}=s^2={10}^{-10}$

$\Rightarrow s={10}^{-5}$

$KN{O}_3\to K^{+}+N{O}_3^{-}$

$\because$ There are no common ions the addition of $KN{O}_3$ has no effect over solubility of $AgCl$

$\therefore$ solubility = ${10}^{-5}$