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Question

KspofAgCl is =2.8×1010 at 25 C. Calculate solubility of AgCl in 0.1 (M) NaCl

A
2.9×105mole lit1
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B
2.6×108mole lit1
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C
2.8×106mole lit1
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D
2.8×109mole lit1
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Solution

The correct option is D 2.8×109mole lit1
AgCl(s)Ag+(aq)+Cl(aq)
s s
KCl(s)K+(aq)+Cl(aq)
0.1 0.1
Ksp=[Ag+][Cl]
=S(0.1+S)
S=2.8×109mole lit1

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