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Question

Ksp of CaSO45H2O is 9×106, find the volume of 1 g of CaSO4(M.Wt.=136)

A
2.45 litre
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B
5.1 litre
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C
4.52 litre
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D
3.2 litre
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Solution

The correct option is A 2.45 litre
CaSO4(s)Ca2+(aq)S+SO24(aq)S

Ksp=S2=9×106

S=3×103mol L1

Solubility in g litre1= molecular mass ×S

=136×3×103=408×103g L1

408×103 g of CaSO4 present in 1 Litre

1 g of CaSO4 present is 1408×103=2.45 litre.

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