Question

Karl Pearson's coefficient of skewness of a distribution is 0.32.Its s.d.is 6.5 and mean is 29.6.The mode and median of the distribution are

• A. 27.52,28.91
• B. 26.92,27.23
• C. 25.67,26.34
• D. none of these

Answer 1

Answer: (A)

27.52,28.91

Karl Pearson's coefficient of skewness $=\frac{Mean-Mode}{S.D.}$ $\therefore 0.32=\frac{29.6-Mode}{6.5}\Rightarrow Mode=27.52$ Also Karl Pearson's coeff.of skewness $=\frac{3(Mean-Median)}{S.D}$ $\because 0.32=\frac{3(29.6-Median)}{6.5}$ $\Rightarrow Median=28.91$