Question

Mean and standard deviation of a frequency distribution of data are $40$ and $10$ respectively. If its coefficient of skewness is $-0.8$ then find mode.

Answer 1

given,

mean = 40 standard deviation = $Sd=10$

coefficient of skewness = $Sk=-0.8$

$Sk=\frac{median-mean}{Sd}$

$-0.8=\frac{median-40}{10}$

$\Rightarrow$ median = $32$

mode + 2median = 3median

mode = 3median - 2mean

mode = $96-80$

= $16$