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Question
Kavita, a student preparing for CSAT, told that she did everyday 3 more passages of English than that of previous day and thus she completed all the passages in 10 days. Later on she told me that the number of passages she did on the last but one day were four times that she did on the second day
Total number of passages that she has completed in those 10 days:
Kavita, a student preparing for CSAT, told that she did everyday 3 more passages of English than that of previous day and thus she completed all the passages in 10 days. Later on she told me that the number of passages she did on the last but one day were four times that she did on the second day
Total number of passages that she has completed in those 10 days:
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Solution
The correct option is C 175
Total number of passages
= x + (x+3) + (x+5) + … + (x+27)
= (4 X 10) + ( 3 + 6 + 9 + …+ 27)
= 40 + 3 (1+2+3+ …+ 9)
=40 + 135 = 175.
Total number of passages
= x + (x+3) + (x+5) + … + (x+27)
= (4 X 10) + ( 3 + 6 + 9 + …+ 27)
= 40 + 3 (1+2+3+ …+ 9)
=40 + 135 = 175.
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