You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Chemistry

Ionic Compounds and Radius Ratios

KCl crystalli...

Question

$K C l$ crystallises in the same type of lattice as $N a C l$ . Given that $r_{N a^{+}} / r_{C l^{-}} = 0.50$ and $r_{N a^{+}} / r_{K^{+}} = 0.70$ , calculate the ratio of the side of the unit cell of $K C l$ to that of $N a C l$ :

1.143

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.224

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.414

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.875

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1.143
Rock salt type lattice structure means the edge length will be $a = r_{+} + r_{-}$
Hence, $\frac{a_{K C l}}{a_{N a C l}} = \frac{r_{K^{+}} + r_{C l^{-}}}{r_{N a^{+}} + r_{C l^{-}}} = \frac{\frac{r_{K^{+}}}{r_{C l^{-}}} + 1}{\frac{r_{N a^{+}}}{r_{C l^{-}}} + 1} = \frac{\frac{0.5}{0.7} + 1}{0.5 + 1} = 1.143$

Suggest Corrections

Similar questions

K C l

crystallises in the same type of lattice as

N a C l

. Given that

r_{N a^{+}} / r_{C l^{-}} = 0.50

and

r_{N a^{+}} / r_{K^{+}} = 0.70

, calculate the ratio of the side of the unit cell of

K C l

to that of

N a C l

Q. KCl crystallizes in the same type of lattice as does NaCl. Given that

\frac{r_{N a +}}{r_{C l -}} = 0.50

and

\frac{r_{N a +}}{r_{K +}} = 0.70

, calculate the ratio of the side of the unit cell for KCl to that of for NaCl.

K C l

crystallises in the same type of lattice as

N a C l

. Given that

r_{N a^{+}} / r_{C l^{-}} = 0.50

and

r_{N a^{+}} / r_{K^{+}} = 0.70

, calculate the ratio of the side of the unit cell of

K C l

to that of

N a C l

K C l

crystallises in the same type of lattice as does

N a C l

. Given that

r_{N a^{+}} / r_{C l^{-}} = 0.55

and

r_{K^{+}} / r_{C l^{-}} = 0.74

. Calculate the ratio of the side of the unit cell for

K C l

to that of

N a C l

KCl crystallizes in the same type of lattice as does NACl. Given that $\frac{r_{N a^{+}}}{r_{C l^{-}}} = 0.55$ and $\frac{r_{K^{+}}}{r_{C l^{-}}} = 0.74$ . Calculate the ratio of the side of the unit cell for KCl to that of NaCl.

Join BYJU'S Learning Program

KCl crystallises in the same type of lattice as NaCl. Given that rNa+/rCl−=0.50 and rNa+/rK+=0.70, calculate the ratio of the side of the unit cell of KCl to that of NaCl:

The correct option is A 1.143Rock salt type lattice structure means the edge length will be a=r++r− Hence, aKClaNaCl=rK++rCl−rNa++rCl−=rK+rCl−+1rNa+rCl−+1=0.50.7+10.5+1=1.143

$K C l$ crystallises in the same type of lattice as $N a C l$ . Given that $r_{N a^{+}} / r_{C l^{-}} = 0.50$ and $r_{N a^{+}} / r_{K^{+}} = 0.70$ , calculate the ratio of the side of the unit cell of $K C l$ to that of $N a C l$ :