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Question

KE of equal masses of methane, oxygen and sulphur dioxide under similar conditions will be in the ratio of:

A
1:1:1
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B
1:2:3
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C
4:2:1
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D
1:2:4
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Solution

The correct option is A 4:2:1
KE=3nRT2
KEn
Thus, KE of gas is inversely proportional to molecular weight of gas, when masses of gases are equal and temperature is also same.
Molecular weight of CH4=16,O2=32,SO2=64

KE1:KE2:KE3=1M1:1M2:1M3

KE1:KE2:KE3=116:132:164=1:12:14=4:42:44=4:2:1
Option C is correct.

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