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Question 10
Keeping the place of 6 in the number 6350947 same, the smallest number obtained by rearranging other digits is 
(A) 6975430
(B) 6043579
(C) 6034579
(D) 6034759


Solution

Given number is 6350947.
The digits in the given number 6350947 are 6, 3, 5, 0, 9, 4 and 7. Keeping the digit 6 at ten lakh's place, the rest of the digits fill other places like lakh, ten thousand, thousands, hundreds, tens and ones place by ascending order of magnitude as 0, 3, 4, 5, 7, 9.
Hence, the required smallest number is 6034579.
 

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