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KF crystalliz...

Question

$K F$ crystallizes in the $N a C l$ type structure. If the radius of $K^{+}$ ions is $132$ pm and that of $F^{-}$ ion is $135$ pm , what is the shortest $K - F$ distance?

267 p m

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534 p m

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378 p m

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N o n e o f t h e a b o v e

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Solution

The correct option is C $267 p m$
$F^{-}$ ions are present in the ccp sites whereas $K^{+}$ ions are present in the octahedral voids.
The shortest distance d between the anion and the cation is given by
$d = r_{+} + r_{-} = 132 + 135$
$d = 267$ pm

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Similar questions

K F

N a C l

K^{+}

132

F^{-}

135

K - K

K^{+}

132

F^{-}

135

K^{+}

F^{-}

2.48

^{- 3}

r_{N a^{+}}

= 95

r_{C l^{-}}

= 181

N a^{+}

K^{+}

F^{-}

K^{+}

F^{-}

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