KMnO4 m-w- - 158 oxidises oxalic acid in acid medium to CO2 and water as follows- 5C2O42- - 2MnO4- - 16H- 10CO2 - 2Mn2- - 8H2OWhat is the equivalent weight of KMnO4-

The correct option is B 31.6 (Oxidation number ofMn = +7)MnO_4^ →(Oxidation number of Mn = +2)Mn^2+ Equivalent mass of KMnO_4 = Molecular massCh ...

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Redox Reactions and Couple

KMnO4 m.w. = ...

Question

$K M n O_{4} (m . w . = 158)$ oxidises oxalic acid in acid medium to $C O_{2}$ and water as follows:
$5 {C_{2} O_{4}}^{2 -} + 2 {M n O_{4}}^{-} + 16 H^{+} \to 10 C O_{2} + 2 M n^{2 +} + 8 H_{2} O$
What is the equivalent weight of $K M n O_{4}$ ?

158

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31.6

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39.5

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79

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Solution

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K M n O_{4}

= 158

C O_{2}

5 C_{2} O_{4}^{2 -} + 2 M n O^{-} + 16 H^{+} \to 10 C O_{2} + 2 M n^{2 +} + 8 H_{2} O

K M n O_{4}

K M n O_{4}

2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

20 m L

K M n O_{4}

K M n O_{4}

2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

K M n O_{4}

K M n O_{4}

2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} ⟶ 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

K M n O_{4}

K M n O_{4}

2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

K M n O_{4}

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