KMnO4 m-w- - 158 oxidises oxalic acid in acid medium to CO2 and water as follows- 5C2O42- - 2MnO4- - 16H- 10CO2 - 2Mn2- - 8H2OWhat is the equivalent weight of KMnO4-

The correct option is B 31.6 (Oxidation number ofMn = +7)MnO_4^ →(Oxidation number of Mn = +2)Mn^2+ Equivalent mass of KMnO_4 = Molecular massCh ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Redox Reactions and Couple

KMnO4 m.w. = ...

Question

$K M n O_{4} (m . w . = 158)$ oxidises oxalic acid in acid medium to $C O_{2}$ and water as follows:
$5 {C_{2} O_{4}}^{2 -} + 2 {M n O_{4}}^{-} + 16 H^{+} \to 10 C O_{2} + 2 M n^{2 +} + 8 H_{2} O$
What is the equivalent weight of $K M n O_{4}$ ?

158

No worries! We‘ve got your back. Try BYJU‘S free classes today!

31.6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

39.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

79

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

K M n O_{4}

= 158

C O_{2}

5 C_{2} O_{4}^{2 -} + 2 M n O^{-} + 16 H^{+} \to 10 C O_{2} + 2 M n^{2 +} + 8 H_{2} O

K M n O_{4}

K M n O_{4}

2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

20 m L

K M n O_{4}

K M n O_{4}

2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

K M n O_{4}

K M n O_{4}

2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} ⟶ 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

K M n O_{4}

K M n O_{4}

2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

K M n O_{4}

Join BYJU'S Learning Program