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Volume of Gases and Number of Moles

Ksp of a Ca...

Question

$K s p$ of a $C a S O_{4} \cdot 5 H_{2} O$ is $9 \times 10^{- 6}$ . Find the volume of $C a S O_{4}$ for $1$ gm.
(Molecular weight $= 236$ g/mol]

A

2.45

litre

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B

5.1

litre

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C

4.52

litre

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D

3.2

litre

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Solution

The correct option is A $2.45$ litre
$K_{s p} = [C a^{2 +}] [S O_{4}^{2 -}]$
$\Rightarrow K_{s p} = S^{2}$
$∴ S = \sqrt{K_{s p}} = \sqrt{9 \times 10^{- 6}} = 3.0 \times 10^{- 3} m o l / L$
$\Rightarrow$ Solubility in $g / L = 3.0 \times 10^{- 3} \times 136 = 408 \times 10^{- 3}$
$∴$ To dissolve $1 g$ of salt= $\frac{1}{0.408} = 2.45 L$ is required

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Similar questions

K_{s p}

C a S O_{4} \cdot 5 H_{2} O

9 \times 10^{- 6}

, find the volume of

1 g

C a S O_{4} (M . W t . = 136)

Q. The experimental data for the reaction;

2 A + B_{2} \to 2 A B

, are as follows. The probable rate expression is:

[A]	[ $B_{2}$ ]	Rate
$m o l l i t r e^{- 1}$	$m o l l i t r e^{- 1}$	$m o l l i t r e^{- 1} s e c^{- 1}$
0.50	0.50	$1.6 \times 10^{- 4}$
0.50	1.0	$3.2 \times 10^{- 4}$
1.00	1.0	$3.2 \times 10^{- 4}$

Q. The experimental data for the reaction,

2 A + B_{2} \to 2 A B

are as follows. Write probable rate expression;

$[A]$ $m o l l i t r e^{- 1}$	$[B_{2}]$ $m o l l i t r e^{- 1}$	$R a t e \times 10^{4}$ $m o l l i t r e^{- 1} {sec}^{- 1}$
$0.50$	$0.50$	$1.6$
$0.50$	$1.00$	$3.2$
$1.00$	$1.00$	$3.2$

Q. Find the temperature at which

3

S O_{2}

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a = 6.71 a t m l i t r e^{2} m o l^{- 2}; b = 0.0564 l i t r e m o l^{- 1}

Q. A sample of hard water contains 0.005 moles of

C a C l_{2}

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2.4 \times 10^{- 5}

25^{\circ} C

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