L-isomer of a compound 'A' $(C_{4} H_{8} O_{4})$ gives a positive test with $[A g (N H_{3})_{2}]^{+}$ . Treatment of 'A' with acetic anhydride yields triacetate derivative. Compound 'A' produces an optically active compound (B) and an optically inactive compound (C) on treatment with bromine water and $H N O_{3}$ respectively. Compound (A) is:

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Solution

The correct option is B

When (A) is heated with acetic anhydride, acetylation ocurs and $- O H$ group is replaced by
and hence, triacetate is formed.

Option C has OH on right hand side so it is not L-isomer.

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