$l ∥ m ∥ n$ and transversals $a$ and $b$ through $A$ intersects them at $A, M, K, N, L$ .If $A N = 7$ cm, $N L = 21$ cm, $K M = 24$ cm, then find the length of intercept $¯ ¯¯¯¯¯¯¯¯ ¯ A M$

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Solution

By intercept theorem, $\frac{A N}{N L} = \frac{A M}{M K}$
$\Rightarrow \frac{7}{21} = \frac{A M}{24}$
$\Rightarrow \frac{1}{3} = \frac{A M}{24}$
$\Rightarrow 3 A M = 24$
$\Rightarrow A M = \frac{24}{3} = 8$ cm
$∴ A M = 8$ cm

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l∥m∥n and transversals a and b through A intersects them at A,M,K,N,L.If AN=7cm,NL=21cm,KM=24cm, then find the length of intercept ¯¯¯¯¯¯¯¯¯¯AM

By intercept theorem,ANNL=AMMK⇒721=AM24⇒13=AM24⇒3AM=24⇒AM=243=8cm∴AM=8cm

$l ∥ m ∥ n$ and transversals $a$ and $b$ through $A$ intersects them at $A, M, K, N, L$ .If $A N = 7$ cm, $N L = 21$ cm, $K M = 24$ cm, then find the length of intercept $¯ ¯¯¯¯¯¯¯¯ ¯ A M$

By intercept theorem, $\frac{A N}{N L} = \frac{A M}{M K}$
$\Rightarrow \frac{7}{21} = \frac{A M}{24}$
$\Rightarrow \frac{1}{3} = \frac{A M}{24}$
$\Rightarrow 3 A M = 24$
$\Rightarrow A M = \frac{24}{3} = 8$ cm
$∴ A M = 8$ cm