Question

${\lambda }_a$ and ${\lambda }_m$ are the wavelengths of the beam of light in air and in medium, respectively. If $\theta$ is the polarizing angle then, the correct relationship between ${\lambda }_a,{\lambda }_m$ and $\theta$ is

• A. ${\lambda }_a={\lambda }_m\tan 2=\theta$
• B. ${\lambda }_m={\lambda }_a{\tan }^2=\theta$
• C. ${\lambda }_a={\lambda }_m\cot =\theta$
• D. ${\lambda }_m={\lambda }_a\cot =\theta$

Answer 1

The correct option is D ${\lambda }_m={\lambda }_a\cot =\theta$

Brewster's angle or polarizing angle is given by $\tan \theta =\frac{n_{medium}}{n_{air}}=\frac{{\lambda }_a}{{\lambda }_m}$

Thus ${\lambda }_m={\lambda }_a\cot \theta$