Laplace transform for the function f(x)=cosh(ax) is
A
as2−a2
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B
ss2−a2
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C
as2+a2
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D
ss2+a2
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Solution
The correct option is Bss2−a2 we know that cosh(ax)=eax+e−ax2
Taking Laplace transform, we get, F(s)=12L{eax}+12L{e−ax} =12[1s−a+1s+a] =2s2(s2−a2) =ss2−a2