Lataben borrowed some money from a bank at a rate of 10 p-c-p-a- interest for 212 years to start a cottage industry- If she paid 10250 rupees as total interest- how much money had she borrowed -

Given: Total interest (I) = 10250 rupees Rate of interest (R) nbsp;= 10 Time (T) = nbsp;212 = nbsp;52 nbsp;years Principal (P) = I #215;100R #215;T ...

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Simple Interest & Compound Interest

Lataben borro...

Question

Lataben borrowed some money from a bank at a rate of $10 %$ per annum interest for $2 \frac{1}{2}$ years to start a cottage industry. If she paid $R s . 10250$ rupees as total interest, how much money had she borrowed ?

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Solution

Given:
Total interest, I $= R s . 10250$
Rate of interest, R $= 10 %$
Time (T) $= 2 \frac{1}{2}$ years
$= \frac{5}{2}$ years
Principal (P) $= \frac{I \times 100}{R \times T}$
$= \frac{10250 \times 100}{10 \times \frac{5}{2}}$
$= R s . 41000$
Hence, Lataben had borrowed $R s . 41000$ from the bank.

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Lataben borrowed some money from a bank at a rate of 10% per annum interest for 212 years to start a cottage industry. If she paid Rs. 10250 rupees as total interest, how much money had she borrowed ?

Given:Total interest, I =Rs. 10250Rate of interest, R =10%Time (T) =212 years=52 yearsPrincipal (P) =I×100R×T=10250×10010×52=Rs. 41000Hence, Lataben had borrowed Rs. 41000 from the bank.

Lataben borrowed some money from a bank at a rate of $10 %$ per annum interest for $2 \frac{1}{2}$ years to start a cottage industry. If she paid $R s . 10250$ rupees as total interest, how much money had she borrowed ?

Given:
Total interest, I $= R s . 10250$
Rate of interest, R $= 10 %$
Time (T) $= 2 \frac{1}{2}$ years
$= \frac{5}{2}$ years
Principal (P) $= \frac{I \times 100}{R \times T}$
$= \frac{10250 \times 100}{10 \times \frac{5}{2}}$
$= R s . 41000$
Hence, Lataben had borrowed $R s . 41000$ from the bank.