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Byju's Answer
Standard XII
Physics
Latent Heat
Latent heat o...
Question
Latent heat of fusion of ice is:
A
336
k
J
k
g
−
1
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B
663
k
J
k
g
−
1
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C
363
k
J
k
g
−
1
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D
636
k
J
k
g
−
1
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Solution
The correct option is
A
336
k
J
k
g
−
1
Latent heat of fusion of ice
=
80
c
a
l
g
−
1
=
80
×
4.2
J
×
10
3
k
g
−
1
=
336
×
10
3
J
k
g
−
1
Suggest Corrections
1
Similar questions
Q.
Assertion :Latent heat of fusion of ice is
336000
J
k
g
−
1
. Reason: Latent heat refers to change of state without any change in temperature.
Q.
400 g of ice at 253 K is mixed with 0.05 kg of steam at
100
o
C
. Latent heat of vaporisation of steam
=
540
c
a
l
g
−
1
. Latent heat of fusion of ice
=
80
c
a
l
g
−
1
. Specific heat of ice
=
0.5
c
a
l
g
−
1
o
C
−
1
. Find the resultant temperature of the mixture.
Q.
Work done in converting one gram of ice at
−
10
∘
C
into steam at
100
∘
C
is -
[Given, specific heat of ice
c
i
=
0.5
cal g
−
1
∘
C
−
1
, specific heat of water
c
w
=
1
cal g
−
1
∘
C
−
1
, latent heat of fusion of ice
L
f
=
80
cal/g
, & latent heat of vaporization of steam
L
v
=
540
cal/g
]
Q.
Calculate the amount of heat reqiured to convert
1
kg
of ice at
−
10
∘
C
into steam at
100
∘
C
. Specific heat capacity of ice is
=
2100
J
k
g
−
1
K
−
1
, latent heat of fusion of ice
=
3.36
×
10
5
J
k
g
−
1
, specific heat capacity of water
=
4200
J
k
g
−
1
K
−
1
and latent heat of vapourization of water
=
2.25
×
10
6
J
k
g
−
1
.
Q.
What is the entropy change in
J
.
K
−
1
during the melting of
27.3
grams of ice at
0
∘
C
?
(Latent heat of fusion of ice
=
330
J
.
g
−
1
)
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