Latent heat of ice is 80 calorie/gm. A man melts 60 g of ice by chewing in 1 minute. His power is

4800 W

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336 W

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1.33 W

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0.75 W

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Solution

The correct option is B 336 W
Work done by man = Heat absorbed by ice = mL = 60 $\times$ 80 = 4800 calorie = 20160 J
$∴ P o w e r = \frac{W}{t} = \frac{20160}{60} = 336 W$

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