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Introduction to Le Chatelier's Principle

Le-chatlier p...

Question

Le-chatlier principle is not applicable for:

H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)

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F e (s) + S (s) ⇌ F e S (s)

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N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

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N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

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Solution

The correct option is B $F e (s) + S (s) ⇌ F e S (s)$
Solution:- (B) ${F e}_{(s)} + S_{(s)} ⟶ {F e S}_{(s)}$
As we know that, Le Chatelier's principle is applicable only to gases.
Thus, it is not applicable for-
${F e}_{(s)} + S_{(s)} ⟶ {F e S}_{(s)}$

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Similar questions

2 H I_{(g)} ⟶ H_{2 (g)} + I_{2 (g)}

2 N H_{3 (g)} ⟶ N_{2 (g)} + 3 H_{2 (g)}

2 N O_{(g)} ⟶ N_{2 (g)} + O_{2 (g)}

P C l_{5 (g)} ⟶ P C l_{3 (g)} + C l_{2 (g)}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); K_{1}

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g); K_{2}

H_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ H_{2} O (g); K_{3}

2 N H_{2} (g) + \frac{5}{2} O_{2} (g) ⇌ 2 N O (g) + 3 H_{2} O (g)

log \frac{K_{p}}{K_{c}} + log R T = 0

log \frac{K_{P}}{K_{C}} + log R T = 0

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); K_{1}

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g), K_{2}

H_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ H_{2} O (g); K_{3}

2 N H_{3} (g) + \frac{5}{2} O_{2} (g) ⇌ 2 N O (g) + 3 H_{2} O (g)

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