1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios Using Right Angled Triangle
1+sinθ +cosθ ...
Question
(
1
+
sin
θ
+
cos
θ
)
2
=
2
(
1
+
sin
θ
)
(
1
+
cos
θ
)
A
True
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
False
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
True
(
1
+
sin
θ
+
cos
θ
)
2
=
1
+
sin
2
θ
+
cos
2
θ
+
2
sin
θ
+
2
cos
θ
+
2
sin
θ
cos
θ
=
1
+
1
+
2
sin
θ
+
2
cos
θ
+
2
sin
θ
cos
θ
=
2
+
2
sin
θ
+
2
cos
θ
+
2
sin
θ
cos
θ
=
2
(
1
+
sin
θ
+
cos
θ
+
sin
θ
cos
θ
)
=
2
(
1
+
sin
θ
)
(
1
+
cos
θ
)
So the given relation is
True
Suggest Corrections
0
Similar questions
Q.
Prove that:
(1+sinθ−cosθ)
2
/(1+sinθ+cosθ)
2
=(1−cosθ)/(1+cosθ)
Q.
Prove the following trigonometric identities.
(i)
sec
θ
-
1
sec
θ
+
1
+
sec
θ
+
1
sec
θ
-
1
=
2
cosec
θ
(ii)
1
+
sin
θ
1
-
sin
θ
+
1
-
sin
θ
1
+
sin
θ
=
2
sec
θ
(iii)
1
+
cos
θ
1
-
cos
θ
+
1
-
cos
θ
1
+
cos
θ
=
2
cosec
θ
(iv)
sec
θ
-
1
sec
θ
+
1
=
sin
θ
1
+
cos
θ
2
(v)
sin
θ
+
1
-
cos
θ
cos
θ
-
1
+
sin
θ
=
1
+
sin
θ
cos
θ