a- a- - a- a- - a-k- a-k- is equal to

The correct option is D 0 Let a= a _ 1 î + a _ 2 ĵ + a _ 3 k̂ . Then a.î = a _ 1 ,a.ĵ = a _ 2 ,a.k̂ = a _ 3 a×î = a _ 2 .k̂ + a _ 3 ĵ ,a×ĵ = ...

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Higher Order Derivatives

a·î a×î + a·ĵ...

Question

$(a \cdot^i) (a \times^i) + (a \cdot^j) (a \times^j) + (a \cdot^k) (a \times^k)$ is equal to

3 a

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a

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0

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None of these

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^i \times (\to a \times^i) +^j \times (\to a \times^j) +^k \times (\to a \times^k)

^i \times ((^a -^j) \times^i) +^j \times ((^a -^k) \times^j) +^k \times ((^a -^i) \times^k) = \to 0

\to a = x^i + y^j + z^k,

8 (x^{3} - x y + z x)

\to a =^i + 2^j +^k, \to b =^i -^j +^k, \to c =^i +^j -^k .

\to a

\to b

\to c

\frac{1}{\sqrt{3}}

^i \times [(a \times b) \times^i] +^j \times [(a \times b) \times^j] +^k \times [(a \times b) \times^k]

^i +^j +^k

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