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Question

(5a5b)a+b.(5b5c)b+c.(5c5a)c+a=

A
1
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B
4
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C
5
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D
0
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Solution

The correct option is A 1
We have, (5a5b)a+b(5b5c)b+c(5c5a)c+a

=(5ab)a+b(5bc)b+c(5ca)c+a

=5a2b25b2c25c2a2
=5a25b25b25c25c25a2=1

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