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Byju's Answer
Standard XII
Mathematics
Relation between AM,GM,HM for 2 Numbers
5a5ba+b.5b5cb...
Question
(
5
a
5
b
)
a
+
b
.
(
5
b
5
c
)
b
+
c
.
(
5
c
5
a
)
c
+
a
=
A
1
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B
4
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C
5
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D
0
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Solution
The correct option is
A
1
We have,
(
5
a
5
b
)
a
+
b
⋅
(
5
b
5
c
)
b
+
c
⋅
(
5
c
5
a
)
c
+
a
=
(
5
a
−
b
)
a
+
b
⋅
(
5
b
−
c
)
b
+
c
⋅
(
5
c
−
a
)
c
+
a
=
5
a
2
−
b
2
⋅
5
b
2
−
c
2
⋅
5
c
2
−
a
2
=
5
a
2
5
b
2
⋅
5
b
2
5
c
2
⋅
5
c
2
5
a
2
=
1
Suggest Corrections
1
Similar questions
Q.
Simplify:
(
5
a
−
5
b
−
5
c
)
2
Q.
If a, b, c are real numbers such that
a
+
b
+
c
=
0
and
a
2
+
b
2
+
c
2
=
1
, then
(
3
a
+
5
b
−
8
c
)
2
+
(
−
8
a
+
3
b
+
5
c
)
2
+
(
5
a
−
8
b
+
3
c
)
2
is equal to.
Q.
If
a
,
b
,
c
,
d
are roots of polynomial
x
4
+
5
x
3
−
4
x
2
+
6
=
0
then the value of
1
a
2
−
5
a
+
6
+
1
b
2
−
5
b
+
6
+
1
c
2
−
5
c
+
6
+
1
d
2
−
5
d
+
6
is
Q.
25
a
5
b
5
c
3
÷
5
a
4
b
4
c
2
=
Q.
Factorise:
Factorization of
8
+
6
(
a
+
b
)
−
5
(
a
+
b
)
2
is
(
4
+
5
a
+
5
b
)
(
2
−
a
−
b
)
If true then enter
1
and if false then enter
0
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