The correct option is
B 2x2−30y2+17xy15Let us solve the given expression as follows:
(15x+2y)(23x−y)=(15x+2×51×5y)(23x−1×31×3y)(TakingLCM)=(15x+105y)(23x−33y)=(x+10y5)(2x−3y3)=115(x+10y)(2x−3y)=115(2x2−3xy+20xy−30y2)=2x2−30y2+17xy15
Hence, (15x+2y)(23x−y)=2x2−30y2+17xy15