7-3 2- 7-3 5 - 7-3 10

Name: EXEMP - Grade 07 - MATHEMATICS - Exponents & Powers - Q59
Uploaded: 2022-07-04T10:36:42+05:30
Description: False Here, ( 7/3 )^2× ( 7/3 )^5 = ( 7/3 )^2+5 = ( 7/3 )^7 Hence,( 7/3 )^2× ( 7/5 )^5≠ ( 7/3 )^10 ...

False Here, ( 7/3 )^2× ( 7/3 )^5 = ( 7/3 )^2+5 = ( 7/3 )^7 Hence,( 7/3 )^2× ( 7/5 )^5≠ ( 7/3 )^10 ...

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Byju's Answer

Standard VII

Mathematics

Exponents with Like Bases

7/3 2× 7/3 5 ...

Question

Question 59
${(\frac{7}{3})}^{2} \times {(\frac{7}{3})}^{5} = {(\frac{7}{3})}^{10}$

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Solution

False
Here, ${(\frac{7}{3})}^{2} \times {(\frac{7}{3})}^{5} = {(\frac{7}{3})}^{2 + 5} = {(\frac{7}{3})}^{7}$
Hence, ${(\frac{7}{3})}^{2} \times {(\frac{7}{5})}^{5} \neq {(\frac{7}{3})}^{10}$

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Similar questions

Q. In the given question, select the related number from the given alternatives.

7

:

32

:

:

35

:

?

Q. Find the square root of

(i)

\sqrt{\frac{2 + \sqrt{3}}{2}}

(ii)

\sqrt{4 + \sqrt{7}}

(iii)

\sqrt{7 + 3 \sqrt{5}}

Question 18

$- 35 \times 107$ is not same as

(a) $- 35 \times (100 + 7)$
(b) $(- 35) \times 7 + (- 35) \times 100$
(c) $- 35 \times 7 + 100$
(d) $(- 30 - 5) \times 107$

Q. Solve

\frac{6}{15} \times \frac{20}{32} \div \frac{35}{8} \times \frac{7}{10} \div 9

Q. Simplify:

(i)

\frac{3 \sqrt{2} - 2 \sqrt{3}}{3 \sqrt{2} + 2 \sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}

(ii)

\frac{5 + \sqrt{3}}{5 - \sqrt{3}} + \frac{5 - \sqrt{3}}{5 + \sqrt{3}}

(iii)

\frac{7 + 3 \sqrt{5}}{3 + \sqrt{5}} + \frac{7 - 3 \sqrt{5}}{3 - \sqrt{5}}

(iv)

\frac{1}{2 + \sqrt{3}} + \frac{2}{\sqrt{5} - \sqrt{3}} + \frac{1}{2 - \sqrt{5}}

(v)

\frac{2}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{2}} + \frac{3}{\sqrt{5} + \sqrt{2}}

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Exponents with Like Bases

Standard VII Mathematics

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Question 59 (73)2×(73)5=(73)10

False Here, (73)2×(73)5=(73)2+5=(73)7 Hence,(73)2×(75)5≠(73)10

Question 59
${(\frac{7}{3})}^{2} \times {(\frac{7}{3})}^{5} = {(\frac{7}{3})}^{10}$

False
Here, ${(\frac{7}{3})}^{2} \times {(\frac{7}{3})}^{5} = {(\frac{7}{3})}^{2 + 5} = {(\frac{7}{3})}^{7}$
Hence, ${(\frac{7}{3})}^{2} \times {(\frac{7}{5})}^{5} \neq {(\frac{7}{3})}^{10}$