a - b- - c- 2-c - a- - b- 2 - a - b- - c- 2-b - c- - a- 2

As we know that ω^3=1,1+ω+ω^2=0 ( a + bω #160; + cω ^2c + aω #160; + bω ^2) + ( a + bω #160; + cω ^2b + cω #160; + aω ^2)= #160; ( aω^3 ...

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Binomial Theorem

a + bω + cω 2...

Question

$(\frac{a + b ω + c ω^{2}}{c + a ω + b ω^{2}}) + (\frac{a + b ω + c ω^{2}}{b + c ω + a ω^{2}})$

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