${({N H}_{4})}_{2} {C r}_{2} O_{7}$ on heating liberates gas. The same gas will be obtained by:

Heating

{N H}_{4} {N O}_{3}

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Heating

{N H}_{4} {N O}_{2}

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Treating

H_{2} O_{2}

with

N a {N O}_{2}

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Treating

{M g}_{3} N_{2}

with

H_{2} O

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Solution

The correct option is B Heating ${N H}_{4} {N O}_{2}$
When $(N H_{4}) C r_{2} O_{7}$ is heating, it liberates $N_{2}$ gas.

${({N H}_{4})}_{2} {C r}_{2} O_{7} Δ - \to N_{2} + {C r}_{2} O_{3} + 4 H_{2} O$

$N_{2}$ gas is also produced when $N H_{4} N O_{2}$ is heated.

${N H}_{4} {N O}_{2} \to N_{2} + 2 H_{2} O$

Hence, option $B$ is correct.

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