Question

${\left({NH}_4\right)}_2{Cr}_2{O}_7$ on heating liberates gas. The same gas will be obtained by:

• A. Heating ${NH}_4{NO}_3$
• B. Heating ${NH}_4{NO}_2$
• C. Treating $H_2{O}_2$ with $Na{NO}_2$
• D. Treating ${Mg}_3{N}_2$ with $H_{2}O$

Answer 1

The correct option is B Heating ${NH}_4{NO}_2$

When $\left(N{H}_4\right)C{r}_2{O}_7$ is heating, it liberates $N_2$ gas.

${\left({NH}_4\right)}_2{Cr}_2{O}_7\underset{}{\overset{\Delta }{\to }}{N}_2+{Cr}_2{O}_3+4H_{2}O$

$N_2$ gas is also produced when $N{H}_{4}N{O}_2$ is heated.

${NH}_4{NO}_2\to N_2+2H_{2}O$

Hence, option $B$ is correct.