Question

$(\sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}})÷\sqrt{\frac{16}{81}}=?$

• A. $\frac{1}{48}$
• B. $\frac{5}{48}$
• C. $\frac{5}{16}$
• D. $\frac{1}{16}$

Answer 1

The correct option is C $\frac{5}{16}$

$(\sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}})÷\sqrt{\frac{16}{81}}=(\frac{15}{27}-\frac{5}{12})÷\frac{4}{9}=(\frac{5}{9}-\frac{5}{12})÷\frac{4}{9}=\frac{5}{36}÷\frac{4}{9}=\frac{5}{36}\times \frac{9}{4}=\frac{5}{16}Answer-OptionC$