Question

Question 88

Length and breadth of the floor of a room are 5 m and 3 m respectively. Forty tiles, each with area $\frac{1}{16}{m}^2$ are used to cover the floor partially. Find the ratio of the tiled to the non-tiled portion of the floor.

Answer 1

Given, length of the floor of a room = 5m
Breadth of the floor of a room = 3m
Area of the room = Length $\times$ Breadth
$=5\times 3=15m^2$
$\because$ Area of $1tile=\frac{1}{16}{m}^2$
$\therefore$ Area of $40tiles=\frac{1}{16}\times 40=2.5m^2$
Area covered by tiles $=2.5m^2$
Area not covered by tiles $=(15-2.5)=12.5m^2$
Ratio of the tiled to non-tiled portion

= $\frac{\text{Area of tiled portion}}{\text{Area of non-tiled portion}}$
= $\frac{2.5m^2}{12.5m^2}=\frac{25}{125}=\frac{1}{5}=1:5$

Hence, the ratio of the tiled to the non-tiled portion of the floor is 1 : 5.