Rakesh wants to cover the floor of a room 4 m wide and 6 m long by square tiles if each square tile is 0-7 m then find the no- Of tiles required to cover the floor of the room

Area of Room = l x b = 4 x 6 = 24 m² Area of each square tile = a² = 0.7 x 0.7 = 0.49 m² Therefore , no of tiles = 24/0.49 = 48.9 = 49 tiles are Required ...

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Standard VI

Mathematics

Area of Square

Rakesh wants ...

Question

Rakesh wants to cover the floor of a room 4 m wide and 6 m long by square tiles. If each square tile is of length 0.7m then, find the no. of tiles required to cover the floor of the room

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Solution

Area of the room $= 4 \times 6 = 24 m^{2}$
Area of one tile $= 0.7 \times 0.7 = 0.49 m^{2}$
Thus, no, of tiles required $= \frac{24}{0.49} = 48$ tiles

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Rakesh wants to cover the floor of a room 4 m wide and 6 m long by square tiles. If each square tile is of length 0.7m then, find the no. of tiles required to cover the floor of the room

Area of the room =4×6=24m2Area of one tile =0.7×0.7=0.49m2Thus, no, of tiles required =240.49=48 tiles

Area of the room $= 4 \times 6 = 24 m^{2}$
Area of one tile $= 0.7 \times 0.7 = 0.49 m^{2}$
Thus, no, of tiles required $= \frac{24}{0.49} = 48$ tiles