Question

Length of the fence of a trapezium shaped field $ABCD$ is $120m$. If $BC=48m$, $CD=17m$ and $AD=40m$. Side $AB$ is perpendicular to the parallel sides $AD$ and $BC$. Find the area of this field.

• A. $660m^2$
• B. $600m^2$
• C. $620m^2$
• D. $630m^2$

Answer 1

The correct option is A $660m^2$

Given, Length of fence of Trapezium $=120m$
$AB+AD+BC+CD=120m$
$\Rightarrow AB=120-(40+48+17)=15m$

Sum of Parallel sides $=AD+BC=40+48=88m$
Height $=AB=15m$

$\text{Area}=\frac{1}{2}\times \text{Sum of parallel sides}\times \text{Distance between them}.$

Area of trapezium $=\frac{(AD+BC)\times h}{2}$

$=\frac{\left(88\right)\left(15\right)}{2}=660m^2$