Question

The length of the fence of the trapezium-shaped field $ABCD$ is $120m$. If $BC=48m,CD=17m$, and $AD=40m$, find the area of this field. Side $AB$ is perpendicular to the parallel sides $AD$ and $BC$.

• A. $660m^2$
• B. $600m^2$
• C. $560m^2$
• D. $480m^2$

Answer 1

The correct option is A $660m^2$


Given: $BC=48m,CD=17m$ and $AD=40m$

Perimeter of $ABCD=120m$

Perimeter of $ABCD=AB+BC+CD+DA$

$120=AB+48+17+40$

$AB=15m$

Area of a trapezoid $=\frac{1}{2}\times (AD+BC)\times AB$

$=\frac{1}{2}\times (40+48)\times 15$

$=\frac{1}{2}\times 88\times 15$

$=44\times 15$

$=660m^2$