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Question

Let 5x2+7y2=140, then (0,0) is:

A
Inside the ellipse
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B
On the ellipse
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C
Outside the ellipse
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D
Centre of the ellipse
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Solution

The correct options are
A Inside the ellipse
D Centre of the ellipse
Equation of ellipse 5x2+7y2=140
Dividing both sides by 140
x228+y220=1
Comparing with (xh)2a2+(yk)2b2=1
(h,k) = (0,0)
Hence (0,0) is centre of given ellipse and it inside the ellipse.

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