Let a 1 - a 2 - a 3 - - - a 15 be in an A-P a 1 - a 2 - - - a 10 - A a 6 - a 7 - - - a 15 - B If B - A - 200 and B - A - 860 - then find a 15

#10; #10;Let first term =a and common difference = d ∴>A=(10/2)[2a+(10 1)d] =5(2a+9d) now B=(10/2)[2a_6+(10 1)d] =5[2 #10;{a+5d}+9 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Collinear Vectors

Let a 1 , ...

Question

Let $a_{1}, a_{2}, a_{3}, \dots, a_{15}$ be in an A.P
$a_{1} + a_{2} + \dots + a_{10} = A$
$a_{6} + a_{7} + \dots + a_{15} = B$ If $B - A = 200$ and $B + A = 860,$ then find $a_{15}$

Open in App

Solution

Suggest Corrections

Similar questions

a_{1}, a_{2}, a_{3}, . . ., a_{15}

a_{1} + a_{8} + a_{15} = 15

a_{2} + a_{3} + a_{8} + a_{13} + a_{14} =

If $a_{1}, a_{2}, \cdot \cdot \cdot, a_{15}$ are in A.P. and $a_{1} + a_{8} + a_{15} = 15$ , then $a_{2} + a_{3} + a_{8} + a_{13} + a_{14}$ equals

If $a_{1}, a_{2}, a_{3} . . . . .$ are in $A . P .$ such that $a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225$ .

a_{1} + a_{2} + a_{3} . . . . . . . . . + a_{23} + a_{24}

a_{1}, a_{2}, a_{3}

a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} =

a_{1} + a_{2} + a_{3} + . . . + a_{23} + a_{24} =

Join BYJU'S Learning Program